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11x^2+141x+268=0
a = 11; b = 141; c = +268;
Δ = b2-4ac
Δ = 1412-4·11·268
Δ = 8089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(141)-\sqrt{8089}}{2*11}=\frac{-141-\sqrt{8089}}{22} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(141)+\sqrt{8089}}{2*11}=\frac{-141+\sqrt{8089}}{22} $
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